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Science & Math for K6 - K12 Students

Home SAT Math Grid in Section Exercise-XIX, XX & XXI
Exercises - XIX,XX &XXI
Exercise-XIX
1.
Sol:
 
 
2. If (a, b) and (a + 3 , b + m) are two points on the line defined by the equation x = 3y – 7 then m =
Sol: x = 3y – 7
  put x = a , y = b , x = a + 3 , y = b + m
  a = 3b – 7
  a – 3b = – 7
  x = a + 3 , y = b + 4
  a + 3 = 3(b + m) – 7
  a + 3 = 3b + 3m – 7
  a – 3b = 3m – 10 (bu t a – 3b = – 7)
  – 7 = 3m – 10
  3m = 10 – 7
  3m = 3
  m = 1
 
 
3. If David loses 8 pounds, he will weigh twice as much as his sister. Together they now weigh 198 pounds. What is David's present weight in pounds ?
Sol: Let David's weight be x pounds
  David's present weight = x – 8 pounds
  sister weight = (x – 8) pounds
  x – 8 + (x – 8) = 198
  2(x – 8) + 1(x – 8) = 198 × 2
  2x – 16 + x – 8 = 396
  3x = 420
  x = 140
  Present weight of David = (140 – 8)
  = 132 pounds
 
 
4. The cost of 12 maps and 10 books is $38 and the cost of 20 maps and 15 books is $ 60. What is the difference between the prices of each item ?
Sol: Let cost of a map be $ x
  Let cost of a book be $ y
 
  12x + 10y = 38
  12 × 1.50 + 10y = 38
  18 + 10y = 38
  10y = 20
  y = 2
  y – x = $ 2 – $ 1.50
  = $ 0.50
 
 
5. A supermarket's total sales for the month of February of this year was $ 384. If the total sales for the same month last year was $ 320 million. What was the percent increase in sales ?
Sol: Increase in sales = $ 384 – $ 320
  = $ 64
  % increase =
  = 20 %
 
 
6. List I : 3 , 6 , 8 , 19
List II : x , 3 , 6 , 8 , 19
If the median of the List I is equal to the median of the numbers in List II , what is the value of x ?
Sol: The median of List I is = 7
  The median of List II is also 7
  The median of x , 3 , 6 , 8 , 19 is 7
  As the median of list II is 7
  3 , 6 , x , 8 , 19 are the numbers
  x = 7
 
 
7. The present ratio of students to teachers in a school is 30. If 50 new students and 5 new teachers join the ratio of students to teachers would then be 25 : 1. What is the present number of students?
Sol: Let the number of students : teachers = 30 x : 1x
  30x + 50 : x + 5 = 25 : 1
  (30x + 50) = 25(x + 5)
  30x + 50 = 25x + 125
  5x = 75
  x = 15
  Number of students = 30 × 15 + 50
  = 500
 
 
8. What is the smallest integer n for which 25n > 512
Sol: (52)n > 512
  (52)6 512
  (52)7 > 512
  514 > 512
  smallest integer n = 7
 
 
9. If 784 = 2a × 7b then the value of 5a + 6b =
Sol: 784 = 28 × 28
  = 7 × 4 × 7 × 4
  = 72 × 42
  2a × 7b = 72 × 24
  a = 4
  b = 2
  5a + 6b = 5 × 4 + 6 × 2
  = 32
 
 
10. If p is the product of the integers from 1 to 20, inclusive what is the greatest integer k for which 5k is a factor of p ?
Sol: 1 × 2 × 3 × 4 × 5 × 6 × 7 × 8 × 9 × 10 × 11 × 12 × 13 × 14 × 15 × 16 × 17 × 18 × 19 × 20
  Product of multiples of 3 = 3 × 6 × 9 × 12 × 15 × 18
  = 3 × 3 × 2 × 3 × 3 × 3 × 4 × 3 × 5 × 3 × 3 × 2
  = 38 × 2 × 4 ×5 × 2
  Greatest integer = 38
  k = 8